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If a + 2b + 2c = 11, 2a + b+ 2c = 10 and...

If `a + 2b + 2c = 11, 2a + b+ 2c = 10 and 2a+ 2b+ c = 9` , What is the value of a ?

A

1

B

2

C

3

D

4

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The correct Answer is:
To find the value of \( a \) from the given equations: 1. **Write down the equations:** \[ \begin{align*} (1) & \quad a + 2b + 2c = 11 \\ (2) & \quad 2a + b + 2c = 10 \\ (3) & \quad 2a + 2b + c = 9 \end{align*} \] 2. **Subtract equation (2) from equation (1) to eliminate \( c \):** \[ (1) - (2): \quad (a + 2b + 2c) - (2a + b + 2c) = 11 - 10 \] This simplifies to: \[ -a + b = 1 \quad \text{(Equation 4)} \] 3. **Now, subtract equation (3) from equation (2) to eliminate \( c \) again:** \[ (2) - (3): \quad (2a + b + 2c) - (2a + 2b + c) = 10 - 9 \] This simplifies to: \[ -b + c = 1 \quad \text{(Equation 5)} \] 4. **Now we have two new equations:** \[ \begin{align*} (4) & \quad -a + b = 1 \\ (5) & \quad -b + c = 1 \end{align*} \] 5. **From equation (4), express \( b \) in terms of \( a \):** \[ b = a + 1 \] 6. **Substitute \( b \) into equation (5) to find \( c \):** \[ - (a + 1) + c = 1 \] This simplifies to: \[ c = a + 2 \] 7. **Substitute \( b \) and \( c \) back into any of the original equations. Let's use equation (1):** \[ a + 2(a + 1) + 2(a + 2) = 11 \] Simplifying this: \[ a + 2a + 2 + 2a + 4 = 11 \] Combine like terms: \[ 5a + 6 = 11 \] Now, isolate \( a \): \[ 5a = 11 - 6 \\ 5a = 5 \\ a = 1 \] 8. **Thus, the value of \( a \) is:** \[ \boxed{1} \]
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