If the ratio of base radius and height of a cone is 1:2 and percentage error in radius is `lambda%` , then the error in its volume is `lambda%` (2) 2`lambda%` (c) 3 `lambda%` (d) none of these

Explanation

We know,Volume of cone `V=1/3pir^2h`


Given, `r/h=1/2`

=`V=2/3pir^3`

`((dV)/(dr))=2pir^2`

Percentage error in measuring `r =lambda%`

=`(Deltar)/r=lambda/100`

=`Deltar=(lambda)/100`

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