The time `t` of a complete oscillation of a simple pendulum of length `l` is given by the equation `T=2pisqrt(1/g)`
where `g` is constant. What is the percentage error in `T` when `l` is increased by 1%?

Explanation

To solve the problem, we need to determine the percentage error in the time \( T \) of a simple pendulum when the length \( l \) is increased by 1%.

The formula for the time period \( T \) of a simple pendulum is given by:

\[ T = 2\pi \sqrt{\frac{l}{g}} \]

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