While measuring the side of an equilateral triangle an error of k% is made, the percentage error in its area

Explanation

side of equilateral `/_= a`

error in side measurement=`k%`

`(da)/a xx 100 = k`

area of an equilateral `/_ = sqrt3/4 a^2 = 5`

`(ds)/(da) = d/(da) ((sqrt3 a^2)/4) = sqrt3/4(2a) `

`ds = sqrt3/2 a*da`

error in area of equilateral `/_ ` will be = `(ds)/s xx 100`

`(ds)/s = ((sqrt3/2)a *da)/((sqrt3/4)a^2)`

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