Home
Class 12
PHYSICS
rho=2g//cm^(3) convert it into MKS syste...

`rho=2g//cm^(3)` convert it into MKS system -

A

`2xx10^(-3)(kg)/(m^(3))`

B

`2xx10^(3)(kg)/(m^(3))`

C

`4xx10^(3)(kg)/(m^(3))`

D

`2xx10^(6)(kg)/(m^(3))`

Text Solution

AI Generated Solution

The correct Answer is:
To convert the density \( \rho = 2 \, \text{g/cm}^3 \) into the MKS system (Kilograms per cubic meter), we will follow these steps: ### Step 1: Convert grams to kilograms We know that: \[ 1 \, \text{kg} = 1000 \, \text{g} \] Thus, to convert grams to kilograms, we can express grams in terms of kilograms: \[ 2 \, \text{g} = \frac{2}{1000} \, \text{kg} = 0.002 \, \text{kg} \] ### Step 2: Convert cubic centimeters to cubic meters Next, we need to convert cubic centimeters to cubic meters. We know that: \[ 1 \, \text{m} = 100 \, \text{cm} \] Therefore, \[ 1 \, \text{cm} = \frac{1}{100} \, \text{m} \] To convert cubic centimeters to cubic meters, we cube both sides: \[ 1 \, \text{cm}^3 = \left(\frac{1}{100} \, \text{m}\right)^3 = \frac{1}{1000000} \, \text{m}^3 = 10^{-6} \, \text{m}^3 \] ### Step 3: Substitute the conversions into the density formula Now we can substitute the conversions into the density formula: \[ \rho = \frac{2 \, \text{g}}{\text{cm}^3} = \frac{0.002 \, \text{kg}}{10^{-6} \, \text{m}^3} \] ### Step 4: Simplify the expression Now we simplify the expression: \[ \rho = \frac{0.002}{10^{-6}} \, \text{kg/m}^3 = 0.002 \times 10^{6} \, \text{kg/m}^3 = 2000 \, \text{kg/m}^3 \] ### Final Answer Thus, the density in the MKS system is: \[ \rho = 2000 \, \text{kg/m}^3 \] ---
Promotional Banner

Topper's Solved these Questions

  • UNIT & DIMENSIONS

    MOTION|Exercise Exercise - 1(Section D-Basic Mathematics)|10 Videos
  • UNIT & DIMENSIONS

    MOTION|Exercise Exercise - 2 (Level - I) (Section A- Units)|4 Videos
  • UNIT & DIMENSIONS

    MOTION|Exercise Exercise - 1(Section B- Dimensions)|6 Videos
  • Thermodynamics

    MOTION|Exercise EXERCISE - 3 SECTION b|26 Videos
  • UNITS AND DIMENSIONS, BASIC MATHEMATICS

    MOTION|Exercise PRACTICE QUESTION|4 Videos

Similar Questions

Explore conceptually related problems

G = 6.67 xx 10^(-11) kg^(-1) m^(3) s^(-2) . Convert it into CGS system.

(a) Density of water in CGS system is g//cm^(3) . Convert it into SI unit. (b) Young's modulus of steel is 2 xx 10^(11) N//m^(2) ( SI unit). Convert in into CGS unit (in "dyne"//cm^(2) ).

In CGS system,the unit of mass is gram g ,length is centimetre cm ,time is second(s),volume is cubic centimetre cm^3 ,force is dyne The density of a material is rho=2g|cm^3 its value in MKS system is

The density of wood is 0.65 g//cm^(3) . The density in SI system is

(a) The unit of coefficient of viscosity in CGS system is poise (g//cm .s) Convert it into SI unit. (b) The SI unit of work is joule, convert it into CGS unit.

The value of gravitation is G = 6.67 xx 10^(-11)N-m^(2)/kg^(2) in SL units . Convert it into CGS system of units .

The density of a substance in C.G.S. system is 0.475 gram//cm^(3) . What is its value in SI system?

What is the moment of inertia os a solid sphere of radius 3 cm and density 3 g//cm^(3) about its diameter in C.G.S. system?

Unit of moment of inertia in MKS system