Find the rate of change of volume of a sphere with respect to its surface area when the radius is 2cm.

Explanation

We know,

`v=4/3pir^3`

`((dv)/(dr))=4pir^2`

Also,`s=4pir^2`

`((ds)/(dr))=8pir`

So,`((dv)/(ds))=r/2=1 (cm^3)/ (c m^2)`

At `r=2`