The solubility of `Ag_(2)CrO_(4)` is `1 xx 10^(-2) "mol"//"lit"`. What is its solubiility product?

Explanation

`AgCrO_(4) rarr 2Ag^(+) + CrO_(4)^(2-)`
`K_(sp) = (2S)^(2) = 4S^(3)`
`= 4 (1 xx 10^(-2))^(2)`
`= 4 xx 10^(-6) M^(3)`
`= 4 xx 10^(-6) M^(3)`