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If HCl is added to pure water at 25^(@)C...

If HCl is added to pure water at `25^(@)C` the ionic product of water will be

A

`gt 10^(-14)`

B

`lt 10^(-14)`

C

`10^(-14)`

D

`gt 10^(-10)`

Text Solution

Verified by Experts

The correct Answer is:
C

At `25^(0)C Kw = 10^(-14) "moles"^(2)//"lit"^(2)`
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