The no. of `H_(3)O^(+)` ions present in `10 mL` of water at `25^(0)C` is

Options

A. `6.023 xx 10^(-14)`
B. `6.023 xx 10^(14)`
C. `6.023 xx 10^(-19)`
D. `6.023 xx 10^(19)`

Answer

B

Explanation

In water
`[H^(+)] = 10^(-7) xx 6.023 xx 10^(23)` ions per liter
in `10`ml solution no.of. `[H^(+)]` ions
`= 10^(-7) xx 6.023 xx 10^(23) xx 10//1000`
`= 6.023 xx 10^(14)`