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K(a) for HCN is 5 xx 10^^(-10) at 25^(@)...

`K_(a)` for `HCN` is `5 xx 10^^(-10)` at `25^(@)C`. For maintaining a constant `pH` of `9.0`, the volume of `5M KCN` solution required to be added to `10mL` of `2M HCN` solution is

A

`5 ml`

B

`2 ml`

C

`6.95 ml`

D

`10.2 ml`

Text Solution

Verified by Experts

The correct Answer is:
B
`P^(H) = P^(ka) + "log"(N_(S)V_(S))/(N_(a)V_(a))`
`9 = 9.3 + "log" (5 xx V_(S))/(2 xx 10)`
`:. V_(S) = 2 ml`
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