Predict the major products in the following reaction:
(i). `C_(6)H_(6)+(CH_(3))_(2)CHCH_(2)OHoverset(H_(2)SO_(4))to` . . .
(ii). `C_(6)H_(5)C_(2)H_(5)underset(2.NaCN)overset(1.Br_(2)" heat,light")to` . . .

Explanation

In this reaction `(CH_(3))_(2)CHCH_(2)OH underset((-H_(2)O))overset(H^(+))tounderset("p-carbonium ion "(by" "H^(-)" shifting"))(CH_(3))_(2)CH-overset(+)(C)H_(2)hArrunderset("t-carbonium ion"("more stable"))(CH_(3))_(2)C^(+)-CH_(3))`
Hence, in this reaction, active species (electrophile) is `(CH_(3))_(3)C^(+)`, so it produces above product as major product.