The force F = `2t^(2)` is applied on the 2 kg block. Then find out the work done by this force in 2sec. Initially at time t = 0, block is at rest.

Explanation

To solve the problem of finding the work done by the force \( F = 2t^2 \) on a 2 kg block over a time interval of 2 seconds, we can follow these steps:

### Step 1: Understand the given force
The force acting on the block is given by:
\[ F(t) = 2t^2 \]

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