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If the diameter of mars is 6760 km and m...

If the diameter of mars is 6760 km and mass one tenth that of the earth the diameter of earth is 12742 km if the acceleartion due to gravity on eath is `9.8 m,s^(-2)` the acceleartion due to gravity on mars is

Text Solution

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We know that `g = ((GM)/(R^(2)))`
So, `(g_(M))/(g_(E)) = ((M_(M))/(M_(E)))((R_(E))/(R_(M)))^(2) = ((1)/(10))((12742)/(6760))^(2)`
`rArr (g_(M))/(g_(E)) = 0.35` or `g_(M) = 9.8 xx 0.35 = 3.48 m//s^(2)`
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