The end product in the reaction is:
`CH_(3)CONH_(2)overset(P_(2)O_(5))rarrBoverset(H_(2),Ni)rarrCoverset(HNO_(2))rarrDoverset(Cu)underset(300^(@))rarrE`

Options

A. `CH_(3)CHO`
B. `CH_(3)COCH_(3)`
C. `CH_(3)COOC_(2)H_(5)`
D. `(CH_(3)CO)_(2)O`

Answer

To find the end product of the given reaction sequence, let's break down each step systematically.

### Step 1: Starting Material
The starting material is **Acetamide (CH₃CONH₂)**.

### Step 2: Reaction with P₂O₅
When acetamide reacts with **P₂O₅**, which is a dehydrating agent, it removes a molecule of water (H₂O). This results in the formation of **Acetonitrile (CH₃C≡N)**.

**Product B: CH₃C≡N**

### Step 3: Hydrogenation with H₂ and Ni
Next, **Acetonitrile** undergoes hydrogenation in the presence of **H₂** and **Ni**. This reaction reduces the triple bond (C≡N) to a double bond (C=NH), resulting in the formation of **Ethylamine (CH₃C(=NH)H)**.

**Product C: CH₃C=NH**

### Step 4: Reaction with HNO₂
The next step involves the reaction of **Ethylamine** with **Nitrous Acid (HNO₂)**. This reaction converts the amine into a diazonium salt, resulting in the formation of **Diazo compound (CH₃C=N₂)**.

**Product D: CH₃C=N₂**

### Step 5: Heating with Copper
Finally, the diazo compound is heated in the presence of **Copper (Cu)** at **300°C**. This reaction leads to the elimination of nitrogen gas (N₂) and results in the formation of **Acetaldehyde (CH₃CHO)**.

**Final Product E: CH₃CHO**

### Conclusion
The end product of the reaction sequence is **Acetaldehyde (CH₃CHO)**.

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