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the reaction, CH(3)COOC(2)H(5) overset(N...

the reaction, `CH_(3)COOC_(2)H_(5) overset(Na+C_(2)H_(5)OH)underset(4[H])rarr C_(2)H_(5)OH+CH_(3)CH_(2)OH` is called:

A

Claisen reduction

B

Clasiden condensation

C

Bouveault Blanc reduction

D

Tischenko reduction

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The correct Answer is:
To solve the question regarding the reaction of ethyl ethanoate with sodium in ethanol, we will break down the steps involved in identifying the type of reaction that occurs. ### Step-by-Step Solution: 1. **Identify the Reactants**: The reaction involves ethyl ethanoate (an ester) and sodium in the presence of ethanol. The chemical formula for ethyl ethanoate is CH₃COOC₂H₅. 2. **Understand the Reaction Conditions**: The presence of sodium (Na) and ethanol (C₂H₅OH) indicates that this is a reduction reaction. Sodium acts as a reducing agent, and ethanol serves as a solvent. 3. **Analyze the Products**: The products of the reaction are two molecules of ethyl alcohol (C₂H₅OH). This suggests that the ester is being reduced to alcohol. 4. **Determine the Type of Reaction**: The specific type of reduction occurring here is known as the Bouin-Blanc reduction. This reaction is characterized by the reduction of carbonyl compounds (like esters) to alcohols using sodium and ethanol. 5. **Conclude the Reaction Type**: Therefore, the reaction can be classified as a Bouin-Blanc reduction, which is a named reaction in organic chemistry. ### Final Answer: The reaction `CH₃COOC₂H₅ + Na + C₂H₅OH → 2 C₂H₅OH` is called a **Bouin-Blanc reduction**.
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Knowledge Check

  • RCH=CH_(2) overset(Na//NH_(2)(l))underset(C_(2)H_(5)OH)to RCH_(2)CH_(3) The reaction is called as:

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    B
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    C
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    D
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  • The given reaction is CH_(3)COOH + C_(2)H_(5)OH overset("Conc." H_(2)SO_(4),Delta)hArr CH_(3)COOC_(2)H_(5) + H_(2)O is called :

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    B
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    D
    Oxidation
  • Number of cross products in the given reaction, CH_(3)COOC_(2)H_(5) + C_(6) H_(5)CH_(2)COOC_(2)H_(5)overset(C_(2)H_(5)Ona// C_(2) H_(5)OH)to will be:

    A
    one
    B
    three
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