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The probability that a student selected at random from a class will pass in Mathematics is `2/3` and the probability that he passes in Mathematics and English is `1/3` . What is the probability that he will pass in English if it is known that he has passed in Mathematics ?

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The correct Answer is:
`therefore P(E//M) = (P(M nn E))/(P(M)) = (1)/((3)/((2)/(3))) = (1)/(cancel3)xx (cancel3)/(2) = 1/2`
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