Calculate the number of unpaired electrons in `Ti^(3+) , Mn^(2+)` and calculate the spin only magnetic moment.

Explanation

Atomic Number of Ti = 22
Electronic configuration of Ti=
`1s^(2) 2s^(2) 2p^(6) 3s^(2) 3d^(2) 4s^(2) `
Electronic configuration of `Ti^(3+)`
`1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(6) 3d^(1)`
Number of unpaired electrons = 1
Spin only magnetic moment `= sqrt(n(n+2))`
Atomic no of Mn = 25
Electronic configuration of Mn = `1s^(2) 2s^(2) 2p^(6 ) 3s^(2) 3p^(6) 3d^(5) 4s^(2)`
electronic configuration of `Mn^(2+)= `
`1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(6) 3d^(5)`
Number of unpaird electrons = 5 .
Spin only magnetic moment = `sqrt(n(n+2))`
`= 5.92 BM`