How is propanoic acid is prepared starting from
an alcohol

Explanation

From an alcohol : Primary alcohols on oxidation in the presence of acidified `K_(2)Cr_(2)O_(7)` or acidified `KMnO_(4)` or alkali `KMnO_(4)` gives the corresponding acids.
`underset("Propanol")(CH_(3)CH_(2)CH_(2))OHunderset((O))overset(K_(2)Cr_(2)O_(7)//H^(+))(to) underset("Propanoic acid")(CH_(3)CH_(2)COOH)`