A car moving uniform motion with speed `"120 kmh"^(-1)` is brought to a stop within a distance of 200 m. How long does it take for the car to stop?

Explanation

Speed `u=120km//h =120xx(5)/(18)`.
`u=33m//s`
Final velocity v = 0, distance = 200 m
We know,
`v^(2)=u^(2)+2as`
`0^(2)=(33)^(2)+2axx(200)`
`a=(-33)^(2)/(2xx200)`
`a=(1089)/(400)="2.722 ms"^(-2)`
As `dv=u+at, 0=33 +(2.72)t, t=(33)/(2.72), t=12.13`