If `vec(A)+2hati-hatj and vecB=4hati+3hatj` then, obtain the scalar magnitude and direction from x - axis of,
`vec(A)+vec(B)`

Explanation

`vecA=2hati-hatj, vecB=4hati+3hatj`
For `vecA+vecB`:
`vecA+vecB=2hati-hatj+4hati+3hatj=6hati+2hatj`
`tan theta=(2)/(6)=(1)/(3), theta=tan^(-1)((1)/(3))`
Magnitude and direction of `vecA+vecB`
`|vecA+vecB|=sqrt((6)^(2)+(2)^(2))=sqrt(36+4)=sqrt(40)=6.3`
Magnitude = 6.3 and direction `theta=tan^(-1)((1)/(3))`