If position of a particle at instant t is given by `x=3t^(2)`, find the velocity and acceleration of the particle.

Explanation

The position of the particle is `x=3t^(2)`
Velocity (v) = ? And acceleration (a) = ?

Velocity of the particle :
`v=(dalpha)/(dt)=(d)/(dt)(3t^(2))" "[because x^(n)=nx^(n-1)]`
`=2xx3t=6t`
Acceleration of the particle :
`a=(dv)/(dt)=(d(6t))/(dt)=6ms^(-2)`