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The time period of a satellite of the ea...

The time period of a satellite of the earth is 5h. If the separation between the earth and the satellite is increased to 4 times the previous value, then what will be the new time period of the satellite acceleration to Kepler's law of period.

Text Solution

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`((T_2)/(T_1))^(2) = ((R_2)/(R_1))^(2) (or) ((T_2)/(5))^(2) = ((4R_1)/(R_1))^(3)`
T_(2) = sqrt(64 xx 25) = 40h`.
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