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Refrigerator is to maintain eatables ...

Refrigerator is to maintain eatables kept inside at `9^(@)C` . If room temperature is `36^(@)C` Calculate the co- efficient of performance.

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Tmeperature `T_(2) = 9^(@)C rArr 273 + 9 = 282 K`
and `T_(1) = 36^(@)C rArr 273 + 36 = 309 K `
Co - efficient of performance `beta =?`
`beta = (T_(2))/(T_(1)-T_(2)) = (282)/(309- 282) = (282)/(27) = 10.4 `
`:. ` Co- efficient of Performance of the refrigerator is `beta = 10.4 `
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