Equal masses of `O_(2)` and `H_(e)` gases are supplied equal amount of heat. Which gas will undergo a greater temperature rise and why?

Explanation

Heat supplied the oxygen = Heat supplied to Helium
`mc_(1)DeltaT_(1)=mc_(2)DeltaT_(2),(DeltaT_(1))/(DeltaT_(2))=(C_(2))/(C_(1))`
As `Cxx(1)/(m),m` = molecular mass.
`(DeltaT_(1))/(DeltaT_(2))=(C_(2))/(C_(1))=(m_(1))/(m_(2)),"As "m_(1)gtm_(2)`
`DeltaT_(1)gtDeltaT_(2)`
`therefore` Therefore oxygen gas is greater temperature rise than the Helium gas.