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A piece of wood of mass m is floating er...

A piece of wood of mass m is floating erect in a liquid whose density is `rho` . If it is slightly pressed down and released, then executes simple harmonic motion. Show that its time period of oscillation is `T=2pisqrt((m)/(Arhog))`

Text Solution

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Spring factor of liquid = A`rho`g
Inertia factor of wood piece = m
Time period `T=2pisqrt(("Inertia factor")/("Spring factor"))`
`T=2pisqrt((m)/(Arhog)`
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