Home
Class 11
PHYSICS
A pendulum is 1.20m long is observer to ...

A pendulum is 1.20m long is observer to have 1m Long is observed to have a period of 2.00s at certain location then the acceleration due to gravity is ,

A

`9.71m//s^(2)`

B

`9.85m//s^(2)`

C

`9.79m//s^(2)`

D

`10.1m//s^(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
the acceleration due to gravity is ,
`g=(4pi^(2))/(T_(p)^(2))l=(4pi^(2))/((2.00)^(2))=(4xx(3.14)^(2))/((4.00s^(2)))xx1`
`=(4xx9.85)/(4.00)=(39.4)/(4)=9.85ms^(-2)`
Promotional Banner

Topper's Solved these Questions

  • OSCILLATIONS

    SURA PUBLICATION|Exercise NUMERICAL PROBLEMS (2 Marks)|5 Videos

  • OSCILLATIONS

    SURA PUBLICATION|Exercise NUMERICAL PROBLEMS (3 Marks)|5 Videos

  • OSCILLATIONS

    SURA PUBLICATION|Exercise LONG ANSWER QUESTIONS|8 Videos

  • NATURE OF PHYSICAL WORLD AND MEASUREMENT

    SURA PUBLICATION|Exercise ADDITIONAL QUESTIONS|241 Videos

  • PROPERTIES OF MATTER

    SURA PUBLICATION|Exercise Value based Questions|5 Videos

Similar Questions

Explore conceptually related problems

Say True or False. At the poles, the acceleration due to gravity is 9.77m//s^(2)

Calculate the time period of a simple pendulum of length one meter. The acceleration due to gravity at the place is pi^2ms^-2 .

In a laboratory experiment with simple pendulum it was found it took 36 s to complete 20 oscillations when the effective length was kept that 80 cm. Calculate the acceleration due to gravity from these data.

The masses of two planets are in the ratio 1:2 their radii are in the ratio 1:2. Find the ratio of the acceleration due to gravity on the planets .