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A particle executing a SHM has maximum a...

A particle executing a SHM has maximum acceleration at a distance of 0.5 cm from its mean position is `2cm//s^(2)` . What will be its velocity when it is at a distance of 1 cm from its mean position.

A

`4cm//s`

B

`2sqrt(3)cm//s`

C

`11.2cm//s`

D

`4sqrt(7)cm//s`

Text Solution

Verified by Experts

The correct Answer is:
B
Acceleration at a point `=omega^(2)y,a=2cms^(-2),y=0.5cm`
`:.a=square^(2)y`
`2=square^(2)xx0.5`
`omega^(2)=2/0.5=4`
`square=2"rad"s^(-1)`
Velocity at any point , `v=omegasqrt(a^(2)-y^(2))`
`square=2,a=2,y=1`
velocity, `v=2sqrt(2^(2)-1^(2))=2sqrt(4-1)=2sqrt(3)cms^(-1)`
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