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A spring compressed by 10 cm develops a ...

A spring compressed by 10 cm develops a restoring force of 10 N.A body of mass 9 kg is placed on it . What is the force constant of the spring ? What is the depression in the spring under the weight of the body? What is the period of oscillation if the body is disturbed from its equilibrium position?

Text Solution

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`F=10N, y = 10cm =0.1m`
Force constant , `k=(F)/(y)=(10)/(0.1)=100N/m`
Further, when F = weight of the body
= `" "=9kg wt +=90N`
`y=F/k=(90)/(100)=0.9m`
Time period , T `=2pi(sqrt(m))/(k)`
`=2pi(sqrt(9))/(100)s=2pi((3)/(10))s`
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