Whet is the ratio between the potential energy the total energy of a particle executing S.H.M, when it's displacement is half of its amplitude?

Explanation

`("Potential energy")/("Total energy")=((1)/(2)momega^(2)y^(2))/((1)/(2)momega^(2)a^(2))=(y^(2))/(a^(2))=((a/2))/(a)=1/4`
`=1:4`