Home
Class 11
PHYSICS
The surface tension of a soap solution i...

The surface tension of a soap solution is `0.03Nm^(-1)` . How much work is done in producing soap bubble of radius `0.05m` ?

Text Solution

Verified by Experts

Given: Surface Tension , `T=0.03N//m`
Work, `W=?`
radius of Soap bubble, `r=0.05m`
Formula: (F) Force `xx` radius (r )
`=4` (Surface Tension `Txx` Area`A`)
`Fxxr=4TA`
`(W)` work=`4T(pir^(2))`
`W=4T(pir^(2))`
`W=4xx0.03xx3.14xx0.05xx0.05`
`=0.000942J`
`W=9.42xx10^(-4)J`
Promotional Banner

Topper's Solved these Questions

  • PUBLIC EXAM QUESTION PAPER MARCH-2019

    SURA PUBLICATION|Exercise Part-III|9 Videos
  • PUBLIC EXAM QUESTION PAPER MARCH-2019

    SURA PUBLICATION|Exercise Part-IV|10 Videos
  • PUBLIC EXAM QUESTION PAPER MARCH-2019

    SURA PUBLICATION|Exercise Part-IV|10 Videos
  • PROPERTIES OF MATTER

    SURA PUBLICATION|Exercise Value based Questions|5 Videos
  • QUARTERLY COMMON EXAMINATION - 2019

    SURA PUBLICATION|Exercise PART - IV|10 Videos

Similar Questions

Explore conceptually related problems

The surface tensions of soap solution is 25 xx 10^(-3) Nm^(-1) . The excess pressure inside a soap bubble of diameter 1 cm is ………….. .

If the surface tension of water is 0.06 Nm^(-1) , then the capillary rise in a tube of diameter 1 mm is (angle of contact = 0^@ ) ………….. .

Surface tension of water is 0.072 Nm^(-1) . The excess pressure inside a water drop of diameter 1.2 mm is:

The amount of the work done in blowing a soap bubble of radius r and surface tension sigma , is:

Air is pushed into a soap bubble of radius r to double its radius, of the surface tension of the soap solution is S, the work done in process is

Find the excess pressure inside (a) a drop of mercury of radius 2 mm (b) a soap bubble of radius 4 mm and (c) an air bubble of radius 4 mm formed inside a tank of water. Surface tension of mercury, soap solution and water are 0.465Nm^-1, 0.03Nm^-1 and 0.076Nm^-1 respectively.