The structure of 4-Methylpent-2-en-1-ol is

Options

A. `CH_(3)CH_(2)CH=CHCH_(2)OH`
B. `(CH_(3))_(2)C=CHCH_(2)CH_(2)OH`
C. `(CH_(3))_(2)CHCH=CHCH_(2)OH`
D. `CH_(3)CH(OH)CH-CH=C(CH_(3))_(2)`

Explanation

To determine the structure of 4-Methylpent-2-en-1-ol, we will follow these steps:

### Step 1: Identify the Parent Chain
The name "pent" indicates that the parent chain consists of 5 carbon atoms. Therefore, we will start by drawing a straight chain of 5 carbon atoms.

### Step 2: Number the Carbon Chain
We need to number the carbon chain to identify the positions of the substituents and functional groups. We will number the chain from the end closest to the double bond to give the lowest possible numbers to the double bond and the alcohol group.

- The numbering will be as follows:
- C1 - C2 - C3 - C4 - C5

### Step 3: Add the Double Bond
The name "pent-2-ene" indicates that there is a double bond between the second and third carbon atoms. We will place a double bond between C2 and C3.

### Step 4: Add the Alcohol Group
The "1-ol" indicates that there is an alcohol (-OH) group on the first carbon. We will place the -OH group on C1.

### Step 5: Add the Methyl Group
The "4-methyl" indicates that there is a methyl group (-CH3) on the fourth carbon. We will add a methyl group to C4.

### Step 6: Draw the Final Structure
Now we can combine all the information to draw the final structure:

1. Draw a straight chain of 5 carbon atoms.
2. Place a double bond between C2 and C3.
3. Attach an -OH group to C1.
4. Attach a -CH3 group to C4.

The final structure can be represented as follows:

```
CH3
|
CH3-CH=CH-CH2-CH2-OH
```

### Summary of the Structure
The structure of 4-Methylpent-2-en-1-ol consists of a 5-carbon chain with a double bond between the second and third carbons, a hydroxyl (-OH) group on the first carbon, and a methyl (-CH3) group on the fourth carbon.

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