The IUPAC name for `CH_(3)CH_(2)CH_(2)CH(CH=CH_(2))CH_(2)CH_(2)CH_(3)` is

Options

A. 4-Ethenylheptane
B. 3-n-propylhex-1-ene
C. 3-Ethenylheptane
D. None of these

Explanation

To determine the IUPAC name for the compound `CH₃CH₂CH₂CH(CH=CH₂)CH₂CH₂CH₃`, we will follow these steps:

### Step 1: Draw the Structure
First, we need to visualize the structure of the compound. The given formula can be expanded to show the carbon chain and the double bond. The structure can be represented as:
```
CH₃-CH₂-CH₂-CH-CH₂-CH₂-CH₃
|
CH=CH₂
```

### Step 2: Identify the Longest Carbon Chain
Next, we identify the longest continuous carbon chain in the molecule. In this case, the longest chain consists of 8 carbon atoms.

### Step 3: Number the Carbon Chain
We will number the carbon chain starting from the end closest to the double bond to give the double bond the lowest possible number. The numbering will be as follows:
```
1 2 3 4 5 6 7 8
CH₃-CH₂-CH₂-CH-CH₂-CH₂-CH₂-CH₃
|
CH=CH₂
```
Here, the double bond is between carbon 4 and carbon 5.

### Step 4: Identify the Substituents
Now, we look for any substituents attached to the main carbon chain. In this case, there is a propyl group (C₃H₇) attached to carbon 4.

### Step 5: Name the Compound
The IUPAC name is constructed by combining the names of the substituents and the main chain. The substituent is named first with its position number, followed by the name of the main chain with the double bond indicated.

- The longest chain is octane (8 carbons).
- The double bond is at position 4, so we use "oct-4-ene."
- The propyl group is at position 3, so we denote it as "3-propyl."

Putting it all together, the IUPAC name of the compound is:
**3-propyl-oct-4-ene**

### Final Answer:
The IUPAC name for `CH₃CH₂CH₂CH(CH=CH₂)CH₂CH₂CH₃` is **3-propyl-oct-4-ene**.

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