Prove that: `t a nthetatan(60^0-theta)tan(60^0+theta)=tan3thetadot`

Explanation

To prove that \( \tan \theta \tan(60^\circ - \theta) \tan(60^\circ + \theta) = \tan 3\theta \), we will start with the left-hand side (LHS) and manipulate it step by step.

**Step 1: Write down the LHS**
\[ \text{LHS} = \tan \theta \tan(60^\circ - \theta) \tan(60^\circ + \theta) \]

**Step 2: Use the tangent subtraction and addition formulas**
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