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Prove that: (sin(A-C)+2sinA+sin(A+C)) / ...

Prove that: `(sin(A-C)+2sinA+sin(A+C)) / ("sin"("B"-"C")+2sinB+"sin"(B+C))`=`(sinA)/(sinB)``

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To prove the equation \[ \frac{\sin(A-C) + 2\sin A + \sin(A+C)}{\sin(B-C) + 2\sin B + \sin(B+C)} = \frac{\sin A}{\sin B} \] we will use the sine addition and subtraction formulas. ...
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