If `alphaa n dbeta` are acute angles such that `t a nalpha=m/(m+1)a n dt a nbeta=1/(2m+1)` , prove that `alpha+beta=pi/4` .

Explanation

To prove that \(\alpha + \beta = \frac{\pi}{4}\) given that \(\tan \alpha = \frac{m}{m+1}\) and \(\tan \beta = \frac{1}{2m+1}\), we can follow these steps:

### Step 1: Use the formula for \(\tan(\alpha + \beta)\)
The formula for \(\tan(\alpha + \beta)\) is:
\[ \tan(\alpha + \beta) = \frac{\tan \alpha + \tan \beta}{1 - \tan \alpha \tan \beta} \]

...