If `(sin(theta+alpha))/(cos(theta-alpha))=(1-m)/(1+m)` , prove that `tan(pi/4-theta)tan(pi/4-alpha)=m`

Explanation

To prove that \(\tan\left(\frac{\pi}{4} - \theta\right) \tan\left(\frac{\pi}{4} - \alpha\right) = m\) given that \(\frac{\sin(\theta + \alpha)}{\cos(\theta - \alpha)} = \frac{1 - m}{1 + m}\), we will proceed step by step.

### Step 1: Rewrite the left-hand side using tangent subtraction formula
We start with the left-hand side:
\[ \tan\left(\frac{\pi}{4} - \theta\right) = \frac{1 - \tan(\theta)}{1 + \tan(\theta)} \]
\[
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