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Energy E of a hydrogen atom with princip...

Energy E of a hydrogen atom with principal quantum number n is given by `E_n=-13.6/n^2 eV`. The energy of photon ejected when the electron jumps from n=3 state to n=2 state of hydrogen is approximately

A

1.9eV

B

1.5eV

C

0.85 eV

D

3.4 eV

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The correct Answer is:
A
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