Home
Class 10
PHYSICS
The energy required to knock out the ele...

The energy required to knock out the electron in the fifth orbit of a hydrogen atom is equal to

A

`13.6 eV`

B

`\frac { + 13.6 } { 25 } e V`

C

`\frac { - 13.6 } { 5 } e V`

D

`\frac { - 13.6 } { 25 } e V`

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • NUCLEAR PHYSICS

    SURA PUBLICATION|Exercise ADDITIONAL QUESTIONS & ANSWER (STATE WHETHER THE FOLLOWING STATEMENTS ARE TRUE OR FALSE : IF FALSE CORRECT THE STATEMENT)|22 Videos
  • NUCLEAR PHYSICS

    SURA PUBLICATION|Exercise ADDITIONAL QUESTIONS & ANSWER (MATCH THE FOLLOWING)|6 Videos
  • NUCLEAR PHYSICS

    SURA PUBLICATION|Exercise ADDITIONAL QUESTIONS & ANSWER (CHOOSE THE CORRECT ANSWER)|67 Videos
  • MODEL QUESTION PAPER HIGHER LEVEL

    SURA PUBLICATION|Exercise Subjective Questions|25 Videos
  • OPTICS

    SURA PUBLICATION|Exercise ADDITIONAL QUESTIONS & ANSWER (Higher Order Thinking Skills (HOTS))|6 Videos

Similar Questions

Explore conceptually related problems

The energy required to knock out the electron in the third orbit of a hydrogen atom is equal to

The energy required to knock out the electron in the seventh orbit of a hydrogen atom is equal to

The energy of the electron in the first orbit of hydrogen atom is -13.6 eV. Its potential energy is

The ratio between the first three orbits of hydrogen atom is

The ratio of kinetic energy to the total energy of an electron in a Bohr orbit of the hydrogen atom is