Home
Class 10
PHYSICS
The ionization energy of hydrogen atom i...

The ionization energy of hydrogen atom is 13.6 eV. Following Bohr's theory, the energy corresponding to a transition between 2nd and 3rd orbit is

A

3.40 eV

B

1.89 eV

C

0.85 eV

D

0.66 eV

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • NUCLEAR PHYSICS

    SURA PUBLICATION|Exercise ADDITIONAL QUESTIONS & ANSWER (STATE WHETHER THE FOLLOWING STATEMENTS ARE TRUE OR FALSE : IF FALSE CORRECT THE STATEMENT)|22 Videos
  • NUCLEAR PHYSICS

    SURA PUBLICATION|Exercise ADDITIONAL QUESTIONS & ANSWER (MATCH THE FOLLOWING)|6 Videos
  • NUCLEAR PHYSICS

    SURA PUBLICATION|Exercise ADDITIONAL QUESTIONS & ANSWER (CHOOSE THE CORRECT ANSWER)|67 Videos
  • MODEL QUESTION PAPER HIGHER LEVEL

    SURA PUBLICATION|Exercise Subjective Questions|25 Videos
  • OPTICS

    SURA PUBLICATION|Exercise ADDITIONAL QUESTIONS & ANSWER (Higher Order Thinking Skills (HOTS))|6 Videos

Similar Questions

Explore conceptually related problems

The ionization energy of hydrogen atom is -13.6eV. The energy corresponding to a transition between 3rd and 4th orbit is

The ground-state energy of hydrogen atom is _______ eV.

The ionisation energy of hydrogen atom is 13.6 eV , the ionisation energy of a singly ionsed helium atom would be

The ground state of energy of hydrogen atom is -13.6 eV .What is the potential energy of the electron in this state?

The ground state energy of hydrogen atom is -13.6 eV. What are k.E & P.E of the electron in this state?

The ground state energy of hydrogen atom is -13.6eV. When its electron is in the first excited state, its excitation energy is

The ground state energy of hydrogen atom is -13.6 eV. When its electron is in the first excited state, its excitation energy is:

Derive the energy expression for hydrogen atom using Bohr atom model.