ABCD is a trapezium in which `AB abs CD` and AD = BC. Show that
`DeltaABC~=DeltaBAD`

ABCD is a trapezium in which AB abs CD and AD = BC. Show that A=B

ABCD is a trapezium in which AB abs CD and AD = BC. Show that C=D

ABCD is a trapezium in which AB abs CD and AD = BC. Show that diagonal AC = diagonal BD

ABCD is a trapezium in which AB||CD and AD=BC Show that angleA=angleB angleC=angleD DeltaABC approx DeltaBAD diagonal AC=diagonal BD

In the given figure, AB||DC and AD||BC show that DeltaABC ~= Delta CDA .

ABCD is a trapezium in which AB abs DC , BD is a diagonal and E is the mid-point of AD. A line is drawn through E parallel to AB intersecting BC at F. Show that F is the mid-point of BC.

In the given Figure AB and CD are intersecting at ‘O’, OA = OB and OD = OC. Show that (i) Delta AOD ~= DeltaBOC and (ii) AD || BC .

ABCD is a trapezium is which AB || CD and BC _|_ AB . If AB = 7.5 cm , AD = 13 cm and CD = 12.5 cm , find the length of BC.

In the adjacent figure DeltaABC, D is the midpoint of BC. DE_|_AB, DF_|_AC and DE = DF . Show that DeltaBED ~= Delta CFD .