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A bombshell of mass explodes such that t...

A bombshell of mass explodes such that the broken masses are in the ratio `1 : 1 : 3`. The ratio two pieces of equal mass fly with the same speed at right angles to each other with a velocity of `100ms^(-1)`. Find the direction and velocity of the third fragment of the shell. What will be the total kinetic energy of the fragments.

Text Solution

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Assume mass of the shell `=m`
Given, `m_(1) : m_(2) : m_(3) : 1 : 1 : 3 `
i.e. `m_(1)=m_(2)=(1)/(5)m` and `m_(3)=(3)/(5)m`
We know that
`0=m_(2)vcos0+m_(1)vcos90^(@)+m_(3)v_(3)cos225^(@)`
i.e. `0=(m)/(5)v+0+(3)/(5)mv_(3)(-(1)/(sqrt(2)))`
i.e. `v=(3)/(sqrt(2))v_(3)`
Given , `v=100ms^(-1)`, hence `v_(3)=(1.414)/(3)xx100`
`v_(3)=47.1ms^(-1)` at `225^(@)` w.r.t to the `X`axis
`KE=KE_(1)+KE_(2)+KE_(3)`
`=(1)/(2)xx(100)/(5)xx(100)^(2)+(1)/(2)xx(100)/(5)xx(100)^(2)+(1)/(2)xx(3)/(5)xx100xx(47.1)^(2)`
`=(1)/(10)(10^(6)(1+1+0.22)`
`:.KE=2.22xx10^(5)J`.
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