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A force of 56.6N is sufficient to pull ...

A force of `56.6N` is sufficient to pull a block of wood of mass `10kg` on a horizontal surface. Calculate the angle of friction.

Text Solution

Verified by Experts

`F=56.6N` `f_(r )=mu_(l)R=mu_(l)mg`, `m=10kg`
For the block to be just pulled,
`F=f_(r )=mu_(l)mg`
`:.mu_(l)=(F)/(mg)` `:. Mu_(l)=(56.6)/(10xx9.8)`
`mu_(l)=0.5775`
but `mu_(l)=tantheta` i.e `tantheta=0.5775~~(1)/(1.732)`
`:.tantheta=(1)/(sqrt(3))` or `theta=30^(@)`
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