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A material breaks with a stress 2.0xx10^...

A material breaks with a stress `2.0xx10^(6)Nm^(-2)` and density `2.5xx10^(3)kgm^(-3)` breaks under his own weight `(g=9.8ms^(-2))`. Calculate its length.

Text Solution

Verified by Experts

`rho=2.5xx10^(3)kgm^(-3)`
Breaking stress `=2xx10^(-6)Nm^(-2)`
Breaking stress `=("Force")/("Area")=("weight of the material of certain length")/("area")`
i.e. breaking stess `=(mg)/A`
but `m=V rho " " m=A l rho`
i..e Stress `=(Al rho g)/a =l rhog`
here `l=("Stress")/(rho g)=(2xx10^(-6))/(2.5xx10^(3)xx9.8)=0.816xx10^(2)m`
`l=81.6m`
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