Estimate the size of fluorine (liquid) molecule, given its atomic mass `19.01u` and density `1.14xx10^(3) kgm^(-3)`.

Explanation

Volume of a single molecule `=("mass of each molecule")/("density")`
`i.e. " " (4)/(3)piR^(3)=(12.01xx1.66xx10^(-27))/(2.22xx10^(3)),1mu=1.66xx10^(-27)kg`
`i.e. " " R_(3)=(3xx12.01xx1.66xx10^(-30))/(2.22xx4xx3.142)=2.144xx10^(-30).`
i.e. radius of each molecule `R=(2.144)^(1/3)xx10^(-10)m=1.289xx10^(-10)m.`
1.289Å