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Calculate the power of an engine interms...

Calculate the power of an engine interms of H.P (Horse power) which needed to lift 1000 kg of coal in 30 minute from a coal mine 100 m deep. (given `g = 9.8 m//s^2` )

Text Solution

Verified by Experts

Given m = 1000 kg
t = 30 minute` = 30 xx 60 = 1800 s`
` h = 100m, g=9.8 ms^(-2)`
wkt ` "power" = ("Potential energy ")/("Time")`
i.e., ` P = (mgh)/(t) = (10^3 xx 9.8 xx 100)/(1800) = 9800/18 W`
i.e., P = 544.44
but `H.P = 746.6W` hence power required
` P = (544.44)/(746.6) = 0.729 HP`
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