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Show that the sum of electrostatic energ...

Show that the sum of electrostatic energy and magnetic energy in an LC oscillator equals `(q_(0)^(2))/(2C)`.

Text Solution

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Total energy = `=U_(E)+U_(m)`
`=(1)/(2)(q_(0)^(2))/(C)cos^(2)omegat+(1)/(2)Lq_(0)^(2)omega^(2)sin^(2)omegat`
`=(1)/(2)(q_(0)^(2))/(C)cos^(2)omegat+(1)/(2)q_(0)^(2)L((1)/(sqrt(LC)))^(2)sin^(2)omegat`
`=(1)/(2)(q_(0)^(2))/(C)cos^(2)omegat+(1)/(2)(q_(0)^(2))/(C)sin^(2)omegat`
`=(1)/(2)(q_(0)^(2))/(C)[cos^(2)omegat+sin^(2)omegat]`
`=(1)/(2)(q_(0)^(2))/(C)`
`q_(0)` and C are time independent constants.
Note :
Maximum energy of a capacitor = maximum energy of an inductor = `(1)/(2)(q_(0)^(2))/(C)=(1)/(2)Li_(m)^(2)`
At any given instant, the total energy, in an LC oscillator is the sum of energy in each of them.
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