Home
Class 12
PHYSICS
About 5% of the power of a 100W bulb is ...

About 5% of the power of a 100W bulb is converted to visible radiation. What is the average intensity of visible adiation.
At a distance 10m ?

Text Solution

Verified by Experts

Intensity at 10m distance and at `5% = 100/(4xx3.142 xx(10)^2) = 0.0796 Wm^(-2)`
At 5%, average intensity of radiation = `0.07896 xx 0.05 = 3.98 xx10^(-3) Wm^(-3)`.
Promotional Banner

Topper's Solved these Questions

  • ELECTROMAGNETIC INDUCTION

    SUBHASH PUBLICATION|Exercise NUMERICALS WITH SOLUTIONS|19 Videos

  • ELECTROSTATIC POTENTIAL AND CAPACITANCE

    SUBHASH PUBLICATION|Exercise NUMERICALS WITH SOLUTIONS|20 Videos

Similar Questions

Explore conceptually related problems

About 5% of the power of a 100W bulb is converted to visible radiation. What is the average intensity of visible adiation. At a distance 1 m from the bulb ?

The period of oscillation of a simple pendulum is T=2pisqrt(L/(g)) . L is about 10 cm and is known to 1 mm accurancy. The period of oscillation is about 0.5 second. The time of 100 oscillation is measured with a wrist watch of 1 s resolution. What is the accurancy in the determination of g ?

5% of the energy supplied to a lamp is radiated as a visible light. How many quanta of light are emitted per second by 100 watt lamp ? Assume the average wavelength of visible light at 555 nm

A bulb of 100 W, 220 V is operated on a line of 110 V then what will be the power consumed ?

In a parallel plate capacitor with air between the plates, each plate has an area of 6xx10^(-3)m^2 and the distance between the plates is 3 m. Calculate the capacitance of the capacitor. If this capacitor is connected to a 100V supply. What is the charge on the each plate of the capacitor?