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Calculate the pH of 0.001 M NaOH.Assumin...

Calculate the `pH` of 0.001 M NaOH.Assuming complete dissociation of base.

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`[OH^(-)]=10^(-3)M" "pOH=-log[10^(-3)]=3`
`pH+pOH=14" "pH=14-3=11`
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