What are free radicals.

What are free radical? How are they formed?

What are the free radicals?

Halogenation is a substitution reaction, where halogen replaces one or more hydrogens of hydrocarbon. Chlorine free radical make 1^(@), 2^(@), 3^(@) radicals with almost equal ease, whereas bromine free radicals have a clear preference for the formation of tertiary free radicals. So, bromine is less reactive, and more slective whereas chlorine is less selective and more reactive. The relative rate of abstraction of hydrogen by Br is {:(3^(@),gt,2^(@),gt,1^(@)),((1600),,(82),,(1)):} The relative rate of abstraction of hydrogen by Cl is {:(3^(@),gt,2^(@),gt,1^(@)),((5),,(3.8),,(1)):} 1-halo-2, 3-dimethyl butane will be obtained in better yields, if halogen is :

Halogenation is a substitution reaction, where halogen replaces one or more hydrogens of hydrocarbon. Chlorine free radical make 1^(@), 2^(@), 3^(@) radicals with almost equal ease, whereas bromine free radicals have a clear preference for the formation of tertiary free radicals. So, bromine is less reactive, and more slective whereas chlorine is less selective and more reactive. The relative rate of abstraction of hydrogen by Br is {:(3^(@),gt,2^(@),gt,1^(@)),((1600),,(82),,(1)):} The relative rate of abstraction of hydrogen by Cl is {:(3^(@),gt,2^(@),gt,1^(@)),((5),,(3.8),,(1)):} Above product will obtained in better yield if X is

Halogenation is a substitution reaction, where halogen replaces one or more hydrogens of hydrocarbon. Chlorine free radical make 1^(@), 2^(@), 3^(@) radicals with almost equal ease, whereas bromine free radicals have a clear preference for the formation of tertiary free radicals. So, bromine is less reactive, and more slective whereas chlorine is less selective and more reactive. The relative rate of abstraction of hydrogen by Br is {:(3^(@),gt,2^(@),gt,1^(@)),((1600),,(82),,(1)):} The relative rate of abstraction of hydrogen by Cl is {:(3^(@),gt,2^(@),gt,1^(@)),((5),,(3.8),,(1)):} CH_(3) - overset(CH_(3))overset(|)(CH) - CH_(3) overset(Cl_(2)//hv)(rarr) Product Major product in the above reaction is :

Halogenation is a substitution reaction, where halogen replaces one or more hydrogens of hydrocarbon. Chlorine free radical make 1^(@), 2^(@), 3^(@) radicals with almost equal ease, whereas bromine free radicals have a clear preference for the formation of tertiary free radicals. So, bromine is less reactive, and more slective whereas chlorine is less selective and more reactive. The relative rate of abstraction of hydrogen by Br is {:(3^(@),gt,2^(@),gt,1^(@)),((1600),,(82),,(1)):} The relative rate of abstraction of hydrogen by Cl is {:(3^(@),gt,2^(@),gt,1^(@)),((5),,(3.8),,(1)):} Which of the following will give five monochloro prodcuts, when allowed to react with Cl_(2) in presence of sun light (excluding stereoisomers) ?

Halogenation is a substitution reaction, where halogen replaces one or more hydrogens of hydrocarbon. Chlorine free radical make 1^(@), 2^(@), 3^(@) radicals with almost equal ease, whereas bromine free radicals have a clear preference for the formation of tertiary free radicals. So, bromine is less reactive, and more slective whereas chlorine is less selective and more reactive. The relative rate of abstraction of hydrogen by Br is {:(3^(@),gt,2^(@),gt,1^(@)),((1600),,(82),,(1)):} The relative rate of abstraction of hydrogen by Cl is {:(3^(@),gt,2^(@),gt,1^(@)),((5),,(3.8),,(1)):} How many dichloro products (including stereoisomers) will be formed when R-2-chloropentane reacts with Cl_(2) in presence of UV radiation ?

Halogenation is a substitution reaction, where halogen replaces one or more hydrogens of hydrocarbon. Chlorine free radical make 1^(@), 2^(@), 3^(@) radicals with almost equal ease, whereas bromine free radicals have a clear preference for the formation of tertiary free radicals. So, bromine is less reactive, and more slective whereas chlorine is less selective and more reactive. The relative rate of abstraction of hydrogen by Br is {:(3^(@),gt,2^(@),gt,1^(@)),((1600),,(82),,(1)):} The relative rate of abstraction of hydrogen by Cl is {:(3^(@),gt,2^(@),gt,1^(@)),((5),,(3.8),,(1)):} What would be the product ratio x/y in the chlorination of propane if all the hydrogen were abstracted at equal rate ? CH_(3) - CH_(2) - CH_(3) underset(hv)overset(Cl_(2))(rarr) CH_(3) - CH_(2) - CH_(2) - Cl + underset((y))(CH_(3) - underset(Cl)underset(|)(CH) - CH_(3))

Halogenation is a substitution reaction, where halogen replaces one or more hydrogens of hydrocarbon. Chlorine free radical make 1^(@), 2^(@), 3^(@) radicals with almost equal ease, whereas bromine free radicals have a clear preference for the formation of tertiary free radicals. So, bromine is less reactive, and more slective whereas chlorine is less selective and more reactive. The relative rate of abstraction of hydrogen by Br is {:(3^(@),gt,2^(@),gt,1^(@)),((1600),,(82),,(1)):} The relative rate of abstraction of hydrogen by Cl is {:(3^(@),gt,2^(@),gt,1^(@)),((5),,(3.8),,(1)):} CH_(3) - underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C) - CH_(2) - overset(CH_(3))overset(|)(CH) - CH_(3) overset(Br_(2)//hv)(rarr) underset("2, Bromo-2, 5, 5 trimethyl pentane (x%)")(CH_(3) - underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C) - CH_(2) - underset(Br)underset(|)overset(CH_(3))overset(|)(C) - CH_(3)) What is the value of x (% yield of product) ?

The most stable free radical is :