An element having atomic mass 63.1 g/mol has face centered cubic unit cell with edge length `3.608 xx 10^(-8)` cm. Calculate the density of unit cell [Given `N_(A) = 6.022 xx 10^(23)` atoms/mol].

Explanation

Data: For fcc lattice z=4
Atomic mass M = 63.1 g
Edge length `u= 3.608 xx 10^(-18)` cm
`N_(A) = 6.022 xx 10^(23)`
Formula `d = (Z xx M)/(a^(2) xx N_(A))`
`d=(4 xx 63.1)/((3.608 xx 10^(-8))^(3) xx 6.022 xx 10^(23))`
`=8.923 g cm^(-3)`